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Mathematics 20 Online
EndersWorld:

Distributive property.

EndersWorld:

\[3xy(2x^2+xy)\]

EndersWorld:

I’m 16

EndersWorld:

almost 17, remember?

Hero:

Thanks for reminding me. Have fun distributing.

EndersWorld:

Gonna call the cops on me? I dunno where to start, it seems weird.

Hero:

Even if I wanted to call the cops (which I don't) but if I did, how would I know what address to give them? Utimately, you are your parents responsibility. I am merely guidance and support. Of course understand that even God did not make a rule that said you must be over a certain age in order to drink certain drinks. That's strictly a manmade rule.

EndersWorld:

Touché, how do I start?

Hero:

Well, for starters the distributive Property still applies. You start by identifying your a, b, and c.

Hero:

Distributive Propery is \(a(b + c) = ab + ac\)

EndersWorld:

a=3xy b=2x^2 c=xy

Hero:

The expression on the outside of the parentheses is always \(a\). The first term in parentheses is always b. The last term in parentheses is always c. Yes exactly

Hero:

Now you may proceed from there with distribution.

EndersWorld:

\[6x^3+3x^2y^2\]

Hero:

You have at least one variable missing from your final result amongst other possible errors.

EndersWorld:

I don’t... um... see one...

EndersWorld:

sigh

Hero:

This is why you should post all your steps. Mind doing so?

EndersWorld:

I uh... did it mentally..

EndersWorld:

1 attachment
Hero:

Yes and it is good practice to do for yourself, but when you are presenting work to others, you should show your steps explicitly.

Hero:

The result you have on paper does not match what you posted here. Do you see that?

Hero:

Observe the difference between what you have on paper and what you posted as your initial answer.

EndersWorld:

A left the y out of \[6x^3y\]

Hero:

Yes. It is otherwise correct.

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