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Mathematics 8 Online
zarkam21:

Find the length

zarkam21:

1 attachment
Vocaloid:

1) use law of cosines (first one) |dw:1525890256383:dw|

zarkam21:

12^2=15^2+c^2

zarkam21:

12^2=15^2+c^2-

Vocaloid:

|dw:1525890427331:dw|

Vocaloid:

you are solving for a, and you are given b, c, and angle A plug them into the formula and solve for a

zarkam21:

a^2=12^2+15^2-2*12*15*cos*a

Vocaloid:

you also need to plug in angle A

zarkam21:

a^2=12^2+15^2-2*12*15*cos110 a=22.18 a^2=492

Vocaloid:

awesome so a is about 22.18 for 2) same thing, solve for the missing side using law of cosines

zarkam21:

we would be solving for c right

Vocaloid:

yes

zarkam21:

c^2=18^2+8^2-(2*18*8)*cos43

zarkam21:

1 attachment
zarkam21:

sorry its taking me a min

Vocaloid:

might be a parentheses issue c^2=18^2+8^2-(2*18*8)*cos(43) otherwise try wolframalpha.com

zarkam21:

1 attachment
Vocaloid:

you need to scroll down to get the value of c

zarkam21:

so -2 and 2

Vocaloid:

Vocaloid:

remember we are talking about a triangle side length so the solution cannot be negative

zarkam21:

so 13.32

Vocaloid:

yes

Vocaloid:

anyway I'm going out for a bit, I'll try to be online in the evening for additional questions

zarkam21:

Sounds good, enjoy

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