Mathematics
8 Online
zarkam21:
Find the length
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zarkam21:
Vocaloid:
1) use law of cosines (first one) |dw:1525890256383:dw|
zarkam21:
12^2=15^2+c^2
zarkam21:
12^2=15^2+c^2-
Vocaloid:
|dw:1525890427331:dw|
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Vocaloid:
you are solving for a, and you are given b, c, and angle A
plug them into the formula and solve for a
zarkam21:
a^2=12^2+15^2-2*12*15*cos*a
Vocaloid:
you also need to plug in angle A
zarkam21:
a^2=12^2+15^2-2*12*15*cos110
a=22.18
a^2=492
Vocaloid:
awesome so a is about 22.18
for 2) same thing, solve for the missing side using law of cosines
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zarkam21:
we would be solving for c right
Vocaloid:
yes
zarkam21:
c^2=18^2+8^2-(2*18*8)*cos43
zarkam21:
zarkam21:
sorry its taking me a min
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Vocaloid:
might be a parentheses issue
c^2=18^2+8^2-(2*18*8)*cos(43)
otherwise try wolframalpha.com
zarkam21:
Vocaloid:
you need to scroll down to get the value of c
zarkam21:
so -2 and 2
Vocaloid:
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Vocaloid:
remember we are talking about a triangle side length so the solution cannot be negative
zarkam21:
so 13.32
Vocaloid:
yes
Vocaloid:
anyway I'm going out for a bit, I'll try to be online in the evening for additional questions
zarkam21:
Sounds good, enjoy