Question

Solve for the remaining sides and angles.

Answer 1

could you just remind me what the formula is

Answer 2

first find a using the first law of cosines formula then go back with law of sines to find angle B or C

Answer 3

a^2 = 32.6^2 + 41.4^2 - 2(32.6)(41.4)cos(pi/6)
solve for a

Answer 4

and ~then~ you'd go back and solve for angle B or angle C w/ law of sines

Answer 5

439.1

Answer 6

keep in mind the formula gives you a^2, you need to take the square root to find a

Answer 7

21

Answer 8

good but let's leave a few more digits

a = 20.9541

now go back and plug in the sides a and b, and the angle A, to find angle B

Answer 9

solve for sin B

Answer 10

20.9541/sin(pi/6) = 32.6/sin(B)
solve for sin(B) and take the arcsin of the result

Answer 11

cross multiplying gives us

20.9541sin(B) = 32.6*sin(pi/6) then isolate sin(B) by dividing both sides by 20.9541 then take the arcsin of both sides to isolate B

Answer 12

2pi

Answer 13

keep in mind 2pi is the same as 360 degrees so that's a clue that something might have gone wrong in your calculations

20.9541/sin(pi/6) = 32.6/sin(B)

sin(B) = 32.6*sin(pi/6)/20.9541

so B = arcsin[32.6*sin(pi/6)/20.9541]

Answer 14

51.07

Answer 15

good, now you have angles B and C, then just gotta solve for angle A using the fact that angles in a triangle sum up to 180

Answer 16

okay so

180-51.07-20.9541

Answer 17

is this right

Answer 18

yup, that'll give you angle A

Answer 19

108

Answer 20

good, so now we have all the angles and all the sides thus, triangle solved