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Physics 8 Online
InTheSea:

For this circuit, what will be the voltage drop across R subscript 2? 14.2 V 45.0 V 9.47 V 21.3 V

InTheSea:

No idea how to approach this one

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InTheSea:

@Shadow

MARC:

The question is asking u to find the votage across \(R_2\) Step 1 : Find the total current for the whole circuit

MARC:

As u can see,the resistors are arranged In series

MARC:

equivalent resistance of resistors in series=\(R_1+R_2+R_3+...\)

MARC:

use this formula \(V=IR_{eff}\) to find the total current where \(V=total~voltage\) \(I=total~current\) \(R_{eff}=effective~resistance\)

Shadow:

\[I_{total} = \frac{ V_{total} }{ R_{total} }\] \[R_{total} = 20 + 30 + 45 = 95 \Omega\] \[I_{total} = \frac{ 45 }{ 95 } = 0.5 A\] \[V = R I\] \[V_{1} = (20)(0.5) = 10 V\] \[V_{2} = (30)(0.5) = 15 V\] \[V_{3} = (45)(0.5) = 22.5 V\] 45 not 12, *facepalm*

Shadow:

I rounded to 0.5 from 0.47, so if you do 30 times 0.47 you would get 14.2

InTheSea:

Thank you! I think I got it :) Sorry for vanishing, I had to deal with something!

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