@nnesha my teacher said some of these are wrong can you help me correct them (4 questions)
@Nnesha
Could you tell me why I did this wrong
@Nnesha
hmm it's larger for sure..
maybe its choice b then instead of C maybe?
yeah but i don't understand why it's not the C since it's negative the image is behind the mirror
or maybe image distance is not negative
this is what it says in my lesson
\[\rm -6.1=\frac{d_i}{d_o}\] if d_o is always positive (according to the table) then for this equation image distance needs to be negative
meaning that the answer is B?
I hvae to fill out this table
no i was trying to figure out why it is not C. BUT if is not C then ofc it is definitely B. other 2 are for smaller
SO would this be the right answer for why it is wrong?
According to this website http://physics.bu.edu/py106/notes/Spherical.html `When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright. A negative m means that the image is inverted. Positive means an upright image.`
My answer was wrong because I incorrectly came to the conslusion that imageis behind the mirror. The correct answer is that it is large and in front.
I need a reason as to why it is the correct answer :(
\(\color{#0cbb34}{\text{Originally Posted by}}\) @zarkam21 My answer was wrong because I incorrectly came to the conslusion that imageis behind the mirror. The correct answer is that it is large and in front. \(\color{#0cbb34}{\text{End of Quote}}\)
you think this is good enough
no
If it was me I will put why i Picked the option C in first place. and will ask teacher why it is not C.
this is also part of my lesson
so from this because it is negative wouldnt it be D , because a negative means the image is small and behind the mirror
oh okay one second
no sign doesn't explain if the image is going to be smaller or larger the number itself will rperesent that
we know that image is 100% larger because 6.1>1
Here is an example of a negative image distance
maybe this will help?
this is about negative mag.
\[\large\rm m=-\frac{d_i}{d_o} \rightarrow -m=\frac{d_i}{d_o}\] if we move the negative sign then it makes sense that d_i is positive which means the image is in front of the mirror. However if we look at this equation mathematically if d_o needs to be positive then di must be negative. so I will ask teacher
okay
I will ask the teacher for this one
\[\rm d_o= \frac{-m}{d_i}\] in order to cancel out negative sign di should be negative
or maybe we just have to ignore that
well they are saying I am wrong and I, myself do not understand why . So if you can figure out why I would sppreciate it. If you dont understand what I did wrong either, I will ask the teacher
B is also wrong ??
No no C is
so b is the right answer ?
if it marked C wrong then yeah B needs to be the answer....
OKay sounds good. can we move on to the next one. (There are 4 )
will see. the last time i did these types of question were like years+infinity ago.. but will try
object and image are on the other sides so image distance needs to be negative
opposite sides*
SO prob choice D
what does the red cross mark represent ? i'm confused
the answer is wrong
that is the answer i submitted but it is wrong
that's what i thought but after your comment `so prop D` i got confusd for a second \[\rm m=-\frac{d_i}{d_o}= -\frac{-10 cm}{20cm}\]
-0.5
but i got that wrong
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha that's what i thought but after your comment `so prop D` i got confusd for a second \[\rm m=-\frac{d_i}{d_o}= -\frac{-10 cm}{20cm}\] \(\color{#0cbb34}{\text{End of Quote}}\) \[\rm m=-\frac{d_i}{d_o}= \color{blue}{-}(\frac{\color{ReD}{-}10 cm}{20cm})\]
ohhhh its 0.5
because of the double negative
yes :=))
yay
would this be a good explanation for why I got it wrong? My answer was wrong because my calculations were wrong. m=− di/do=−(-10cm)/(20cm). The answer is 0.50 because of the double negative and I put -0.50
yes you can say that but my explanation will be different
is this a online class ?
yes it is
what would your explanation be
I don't think your mistake was multiplying two negative values.. You didn't realize that the image distance needs to be negative. so if it was me i will mention that to my teacher that I couldn't figure out that Di needs to be negative because image and the object are on opposite side that's how your teacher will understand that you're trying your best but having difficult time to catch the key points maybe she/he will help you with that
Yeah true
shall we continue to the last one
last one ? yayya sure
actually second to last one
there is one more after this
hmm what do you think the answer should be now after figuring out the first question we did together ?
D

D?
well first of all m >1 or m <1 ??
Yes that is true
it is less than
hmm ignore the sign for now
from yesterday post ` when m is negative => the image is inverted` `when m is positive => the image is upright` `when m is greater than 1 => image is larger than the object` `when m is less than 1 => image is smaller than the object``
when m is less than 1 => image is smaller than the object`
thsi is the one we should look at because it is smaller than 1
If i'm not wrong we need to look at sign and the value separately because they both represent different things
inverted and smaller than
when m is negative => the image is inverted when m is less than 1 => image is smaller than the object`
m= 2 ignoring the sign is 2<1 or 2>1 ?
2>1
yes so m is greater than m
okay so fromt hat we can see that it is larger than the object
yes
so choice c
we have one more
yes C because m is negative and di is positive so it should be real image
ohh we did that one yesterday hmm I was confused about that one bec if we just look at the table both virtual are negative..
maybe retrying witht he lessons I showed ? :/ (
where are the lessons ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @zarkam21 \(\color{#0cbb34}{\text{End of Quote}}\)
hold on
hmm I agreed to D after watching this video yesterday https://www.khanacademy.org/science/physics/geometric-optics/lenses/v/thin-lens-equation-and-problem-solving @8.25
Did you find the answer
maybe A
because that would be the opposite
no i won't pick A
Then?
the negative indicates it is virtual
SO B
i'm still looking for more info maybe 5 minutes ?
yeah sure no prob take your time
http://www.khadley.com/courses/Physics/ph_212/topics/rayOptics/images/slide32.png?crc=493359552 yeah i'll go with B
if the image distance is negative the image will be virtual according to that ^^both can have virtual image
Join our real-time social learning platform and learn together with your friends!