Question

The function g(n) = n2 − 20n + 95 represents a parabola.

Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points)

Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points)

Part C: Determine the axis of symmetry for g(n). (2 points)

Answer 1

@dude

Answer 2

Do you have an idea on how to approach this?

Answer 3

y = n^2 - 20n + 95?
this what i think it suppose to be but not sure

Answer 4

then
y - 95 = n^2 - 20n?

Answer 5

@ThisGirlPretty

Answer 6

@563blackghost

Answer 7

@Angle

Answer 8

vertex form is: y = a(x - h)^2 + k
where a is the stretch factor
and the point (h, k) is the vertex

Answer 9

Have you learned how to "complete the square" ?

Answer 10

yes a little bit but i get confused with it

Answer 11

so it would be y=a(x-0)^2+95?

Answer 12

nope
there's more steps

Answer 13

ok then can you walk me through den preaze e.e

Answer 14

FOR EXAMPLE
how would you factor: n^2 - 20n + 100 ?

Answer 15

ummmmmm........

i think you break them into 2 groups like (n^2-10n)+(-10n+100) (the two tens is the 20 spilt)

Answer 16

am i correct?

Answer 17

yup that's the correct first step

Answer 18

Wait so its like
g(n)= n^2-20n+95
Step 1: n^2 - 20n + 100
Step 2: break them in two (n^2-10n)+(-10n+100)

Answer 19

@Angle Yew still der e.e

Answer 20

and keep factoring

Answer 21

=n(n-10)-10(n-10)

Answer 22

Then Then it equals (n-10) (n-10) which also equals (n-10)^2

Answer 23

is that correct

Answer 24

?????????????????????

Answer 25

@Angle

Answer 26

Hello? i need this done soon is 9:00pm pleaseee

Answer 27

@ThisGirlPretty Can you help at all?

Answer 28

@dude

Answer 29

Yes (n-10) (n-10) does turn into \((n-10)^2\)

Answer 30

So whats the next step

Answer 31

its 9:00 PM and i need to get this and one more question done can you please help me and go fast

Answer 32

G(n)=(n-10)^2

^the over all answer for part A

Answer 33

Reminder of how this equation is set up \(\bf ax^2+bx+c\)
Not sure what Angle's approach was but if you want to complete the square you need to do obtain the b value in the equation and
\((\frac{b}{2})^2\)
So \((\frac{-20}{2})^2=-10^2=100\)
We add it inside the parenthesis and subtract it when its outside to keep a balance and not change the equation itself
\((n^2-20n~\color{red}{+100}~)+95\color{red}{-100}\)
So from here we can just factor
\((n-10)(n-10)-5\)
Which is just \((n-10)^2-5\)

Answer 34

Wait so its like
g(n)= n^2-20n+95
Step 1: n^2 - 20n + 100
Step 2: (b over 2) ^2 So (-20 over 2) ^2=-10^2=100
Step 3: (n^2-20n=100)=95-100
Step 4: (n-10) (n-10)- 5
Step 5: (n-10)^2 - 5
Answer G(n)=(n-10)^2-5