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Mathematics 21 Online
Allison:

3a^3b^3/4b

dude:

\(\frac{3a^3b^3}{4b}\) They both have a b in common \(\frac{3a^3b^{3\color{red}{-1}}}{4b^{1\color{red}{-1}}}\rightarrow \boxed{\frac{3a^3b^2}{4}}\)

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