help please
@dude
first we divide both sides by 4 what does that get you?
\(6^{3x} = 55.25\) then we want to put this in a log form |dw:1526862491135:dw|
I'll provide the general outline of what you should do next, seeing as you have logged off: the next step would be to get x all alone. then we want the log to be a base 10 instead of base 6 we can do that with this idea: |dw:1526862768097:dw|
doing that would get you to your answer if you get stuck along the way, feel free to tag me when you come back
alright
@Angle
what part did you need help with?
i just still dont get it completely, it's just strange to me
I understand that, lol, even I had to google the equations they're sometimes weird to use what have you gotten so far?
my mind says it's C, but i just dont think it is
it's not C here, I got you to this step: \(6^{3x} = 55.25\) what happens next?
|dw:1526866383517:dw|
b = 6 c = 3x a = 55.25
okay..
b = 6 c = 3x a = 55.25 plug that into \(log_b (a) = c\)
so log_6 (55.25) = 3x
awesome! then we want to solve for x so divide both sides by 3
eh...
(1/3) log_6 (55.25) great awesome then |dw:1526866908209:dw| plug in x = 55.25 a = 6 and b you can just leave blank
okay..
what do you get? plug in x = 55.25 a = 6 \(\large \frac{log(x)}{log(a)}\)
oh, log55.25/log6
A?
tah dahhh A is correct
can you help with one more?
post it as a new question
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