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Mathematics 29 Online
princeevee:

help please

princeevee:

1 attachment
princeevee:

@dude

Angle:

first we divide both sides by 4 what does that get you?

Angle:

\(6^{3x} = 55.25\) then we want to put this in a log form |dw:1526862491135:dw|

Angle:

I'll provide the general outline of what you should do next, seeing as you have logged off: the next step would be to get x all alone. then we want the log to be a base 10 instead of base 6 we can do that with this idea: |dw:1526862768097:dw|

Angle:

doing that would get you to your answer if you get stuck along the way, feel free to tag me when you come back

princeevee:

alright

princeevee:

@Angle

Angle:

what part did you need help with?

princeevee:

i just still dont get it completely, it's just strange to me

Angle:

I understand that, lol, even I had to google the equations they're sometimes weird to use what have you gotten so far?

princeevee:

my mind says it's C, but i just dont think it is

Angle:

it's not C here, I got you to this step: \(6^{3x} = 55.25\) what happens next?

Angle:

|dw:1526866383517:dw|

Angle:

b = 6 c = 3x a = 55.25

princeevee:

okay..

Angle:

b = 6 c = 3x a = 55.25 plug that into \(log_b (a) = c\)

princeevee:

so log_6 (55.25) = 3x

Angle:

awesome! then we want to solve for x so divide both sides by 3

princeevee:

eh...

Angle:

(1/3) log_6 (55.25) great awesome then |dw:1526866908209:dw| plug in x = 55.25 a = 6 and b you can just leave blank

princeevee:

okay..

Angle:

what do you get? plug in x = 55.25 a = 6 \(\large \frac{log(x)}{log(a)}\)

princeevee:

oh, log55.25/log6

princeevee:

A?

Angle:

tah dahhh A is correct

princeevee:

can you help with one more?

Angle:

post it as a new question

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