Question

Consider the following equilibrium system:

2 NO(g)+Cl2(g)⇌2 NOCl(g).

At a certain temperature, the equilibrium concentrations are as follows: [NO]=0.184 mol/L, [Cl2]=0.165 mol/L, and [NOCl]=0.060 mol/L. What is the equilibrium constant for this reaction?

Answer 1

@Vocaloid

Answer 2

in essence:

[concentration of product]^molar coefficient * [concentration of product]^molar coefficient]

divided by

[concentration of reactant]^molar coefficient * [concentration of reactant]^molar coefficient]

applying this to our problem gives us

K = [NOCl]^2 / ( [NO]^2 * [Cl2] ) = plug in the values and solve