nhoraq:

Consider the following equilibrium system: 2 NO(g)+Cl2(g)⇌2 NOCl(g). At a certain temperature, the equilibrium concentrations are as follows: [NO]=0.184 mol/L, [Cl2]=0.165 mol/L, and [NOCl]=0.060 mol/L. What is the equilibrium constant for this reaction?

2 months ago
ThisGirlPretty:

@Vocaloid

2 months ago
Vocaloid:

|dw:1526951595047:dw|

2 months ago
Vocaloid:

in essence: [concentration of product]^molar coefficient * [concentration of product]^molar coefficient] divided by [concentration of reactant]^molar coefficient * [concentration of reactant]^molar coefficient] applying this to our problem gives us K = [NOCl]^2 / ( [NO]^2 * [Cl2] ) = plug in the values and solve

2 months ago
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