help please!!
I just learned this not too long ago, let me see if I can go back to those lessons and example to you how to do it c:
How would you approach this one Paris? It's a bit similar to the ones we did before.
Emphasis on the word similar (:
I'm not too sure how you got the 1.5
I got 1.5 because the two figures were similar to each other. That means that there is some common factor between the two figures that I can use to find the measure of the lengths on the other figure. Here we can solve it two ways. \[\frac{ 20 }{ x } = \frac{ 16 }{ 4 }\] \[16x = 80\] \[x = 5\] Or we can find the common factor, as we did earlier \[16a = 4\] \[a = \frac{ 4 }{ 16 } = \frac{ 1 }{ 4 }\] \[20 \times \frac{ 1 }{ 4 } = 5\]
So x would be 20?
No. Look at my final answer for the two different ways that I solved this problem.
So x=5?
yes
Thank you!! I have about 5 more I need help on do you mind?
Have to leave for school. You can try asking Vocaloid, she's smart.
Okay thank you!!
No problem
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