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Math help please?
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@Vocaloid @ShadowWolf @Angle @hero
@563blackghost
draw it on an argand diagram
alright, you have a + bi arctan(b/a) will give you the angle, sqrt(a^2+b^2) will give you the coefficient (A) for A(cos(theta) + isin(theta))
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would you like to try answer choice A? 1 + i taking the coefficients gives us a = 1 and b = 1 can you try calculating arctan(b/a) and r = sqrt(a^2 + b^2)?
artan 1/1 r=sqrt1^2+1^2 = R=sqrt2?
good, and arctan(1/1) is pi/4 so putting it back into polar form gives sqrt(2)(cos(pi/4) + isin(pi/4)) which conveniently matches answer choice A, got lucky this time
Thanks!
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