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Mathematics 7 Online
zarkam21:

Compute the modulus and argument of each complex number.

zarkam21:

1 attachment
zarkam21:

r=sqrtx^2+y^2 right

Vocaloid:

yes

Vocaloid:

be careful with parentheses modulus = sqrt(x^2+y^2)

zarkam21:

okay so 0

zarkam21:

sqrt(x^2+y^2) sqrt((1)^2+(i)^2) =0

Vocaloid:

for modulus and theta calculations don't include i, but do include the coefficient so 1 + i gives us x = 1 and y = 1

zarkam21:

sqrt(x^2+y^2) sqrt((1)^2+(1)^2) =sqrt2

Vocaloid:

good, keep going

zarkam21:

sqrt(x^2+y^2) sqrt((4)^2+(-4)^2)=4sqrt2 sqrt(x^2+y^2) sqrt((2)^2+(5)^2)=sqrt29

Vocaloid:

good

zarkam21:

for part IV i kinda forgot how to do iit :/

Vocaloid:

the argument is just the theta value inside cos and sin the modulus is the number out in front (2)

zarkam21:

okay so modulus = 2 argument = 2pi/3

zarkam21:

what about the argument for the other ones,

Vocaloid:

theta = arctan(y/x).

zarkam21:

arctan (5/2)= 68.2 degrees (PartIII)

zarkam21:

arctan (4/4) = pi/4 = 45degrees (Part II)

zarkam21:

arctan (1/1)=pi/4=45degrees (Part I)

Vocaloid:

check your sign on part II, it's 4 - 4i so it should be arctan(-4/4)

zarkam21:

arctan (-4/4) = -pi/4 = -45degrees (Part II)

Vocaloid:

good, since we'd usually want a positive theta you can just add 360 degrees (or 2pi) to that

zarkam21:

=315 degrees

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