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Find the sum of the summation of 2 i minus 9, from i equals 3 to 10 .
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Sn = (n/2)(a1+an) you have 8 terms from i = 3 to 10 (term 3,4,5,6,7,8,9,10) so n = 8 to find a1, plug in n = 3 into the sequence 2i - 9 to find an, plug in n = 10 into the sequence 2i - 9 then calculate Sn
i don't understand.. where would i plug the 3 into for the sequence 2i-9?
oh whoops meant to say i = 3 and i = 10 since i is the index not n so you would just let i = 3 and calculate 2i - 9
oooohh okay! thank you
so it'd be; Sn=(8/2)(-3+11).. am i doing this right so far?
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yes, then you would just evaluate that product
so the answer would be Sn=32.?
yup good
thank you so much!
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