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Mathematics 14 Online
zarkam21:

.

zarkam21:

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zarkam21:

@Vocaloid

zarkam21:

A and c

Vocaloid:

are the statements at the end supposed to be equal signs? sin^2(x) + cos^2(x) = 1?

zarkam21:

oh yes

zarkam21:

=1

Vocaloid:

then yes, I agree

zarkam21:

just a and c?

Vocaloid:

yes

zarkam21:

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zarkam21:

A and C

zarkam21:

D

Vocaloid:

there should only be two solutions solving for cos^2(2x) gives us cos(2x) = 1/2 then figure out what angles on the UC give a cos value of 1/2 then divide the results by 2

zarkam21:

c and d

Vocaloid:

good

Vocaloid:

wait a minute i forgot to consider the -1/2 solutions ugh

zarkam21:

its ok

zarkam21:

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zarkam21:

C

Vocaloid:

good

zarkam21:

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zarkam21:

B

zarkam21:

C

zarkam21:

you there :)

Vocaloid:

still working on the calculations I don't think pi/4 is a solution using the sin difference rule I get sin(3x-x) = 0 can you try solving this for x

zarkam21:

pi/2

zarkam21:

x=pi?

Vocaloid:

good and there's only one choice that includes both pi/2 and pi, which one is it?

zarkam21:

a

zarkam21:

actually b?

Vocaloid:

note: we stated earlier that pi/4 is not a solution

zarkam21:

so a

Vocaloid:

good

zarkam21:

.

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zarkam21:

a

Vocaloid:

almost, 3pi/4 + 2pi*k is only one of the solutions; solving for 2cos(x) + sqrt(2) = 0 gives cos(x) = -sqrt(2)/2 and there's one more value on the UC where cos(x) = -sqrt(2)/2

zarkam21:

d

zarkam21:

no b

zarkam21:

right

Vocaloid:

well, is it 5pi/4 or 7pi/4 where cos(x) = -sqrt(2)/2?

zarkam21:

d

Vocaloid:

good, D

zarkam21:

its 5pi/4

zarkam21:

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zarkam21:

A and c

Vocaloid:

almost if you want to multiply the r-value by -1 you have to add pi to the angle not 2pi

zarkam21:

d

zarkam21:

so a and d

Vocaloid:

good, A+D

zarkam21:

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zarkam21:

C

Vocaloid:

a= 200 and b = 134?

zarkam21:

yes side a and b

Vocaloid:

angle B cannot be 141.92 degres because angle A is already 113 degrees

Vocaloid:

it would make the sum of the triangle > 180

zarkam21:

so a

Vocaloid:

good

zarkam21:

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Vocaloid:

got to go to lunch pretty soon but you would just use law of cosines

zarkam21:

ok

zarkam21:

b^2 right

zarkam21:

7.39?

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