Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?

Answer 1

Hello!

so

centripetal acceleration = (speed)^2 / (radius)

Answer 2

in this case,
speed = 0.15
and
acceleration = 0.43

we plug this in to get
0.43 = (0.15)^2 / (radius)

now all we have to do it solve for the radius

Answer 3

thanks