Vocaloid:

Just need some help drawing out some of the intermediary steps in this dichlorocarbene reaction

4 months ago
Vocaloid:

I am given cyclohexene, which reacts w/ KOC(CH3)3 and CHCl3 to make |dw:1529692234669:dw|

4 months ago
Vocaloid:

like, I think that the double bond gets attacked by CCl2 but not sure how to get to that step

4 months ago
MARC:

|dw:1529720201812:dw|

4 months ago
MARC:

|dw:1529720526112:dw|

4 months ago
MARC:

|dw:1529720749135:dw|

4 months ago
MARC:

|dw:1529720820165:dw||dw:1529720830294:dw|

4 months ago
MARC:

|dw:1529721012334:dw||dw:1529721074380:dw|

4 months ago
MARC:

we must remove the rather acidic proton from CHCl3 to give the carbanion. This loses chloride to give dichlorocarbene and insertion into cyclohexene gives the product.

4 months ago
Vocaloid:

makes sense, thank you ~

4 months ago
MARC:

yw! ^

4 months ago
Similar Questions: