Question

Just need some help drawing out some of the intermediary steps in this dichlorocarbene reaction

Answer 1

I am given cyclohexene, which reacts w/ KOC(CH3)3 and CHCl3 to make

Answer 2

like, I think that the double bond gets attacked by CCl2 but not sure how to get to that step

Answer 3

we must remove the rather acidic proton from CHCl3 to give the carbanion. This loses chloride to give dichlorocarbene and insertion into cyclohexene gives the product.

Answer 4

makes sense, thank you ~

Answer 5

yw! ^