Question

HELP! DATA MANAGEMENT
A brown-eyed father and a green-eyed mother have a 25% chance of having a green-eyed child. What is the probability that, in a family of four children, three of them have green eyes?

Answer 1

@Vocaloid help?

Answer 2

25% chance of one green-eyed child
75% chance of a non-green-eyed child

so 3 green-eyed and one brown-eyed gives us

(25%)(25%)(25%)(75%)

there are 4 possible ways this can happen
GGGB, GGBG, GBGG, BGGG, so simply multiply the previous probability by 4

4*(25%)(25%)(25%)(75%) ==> convert to a decimal

Answer 3

so the answer is 4.6875 right?

Answer 4

alright thanks for clearing it up!!!

Answer 5

4 * .25 * .25 * .25 * .75 = ?

Answer 6

@Vocaloid @pennyproud I think the answer is
0.046 875

Answer 7

good

Answer 8

thanks also for the sum question
isn't it either 2 or infinite

Answer 9

oh wait it can be zero because zero is equal because both sides r 0 @Vocaloid

Answer 10

can we not interrupt each other's questions kthnx

Answer 11

like the sum is zero which is equal

Answer 12

I answered Pennys question I didn't interupte

Answer 13

the sum of a probability distribution is always 1

Answer 14

anyway i'm going to close this

Answer 15

thanks jamie and vocaloid