Question

Let f(x) = 2x − 6. Solve f−1(x) when x = 2.

Answer 1

\[f(x) = 2x - 6\]
\[f(x)=2(x) - 6\]
\[y=2(x)-6\]
\[x=2y-6\]
\[+6 +6\]
\[\frac{ 2-6 }{ 2 }\]
\[\frac{ 2y }{ 2 }\]
\[\frac{ 2-4 }{ 2 } = f^1(x)\]

Answer 2

^how did i do so far

Answer 3

@TheSmartOne

Answer 4

Made a mistake
You added 6 but then when you went to the next line you're subtracting it

Answer 5

wait huh let me look

Answer 6

And then after that line I'm not sure what happened

Answer 7

i see i was looking at my notes and put what the note said

Answer 8

\[\frac{ 2+6 }{ 2 }\] \[\frac{ 2y }{ 2 }\]
\[\frac{ 8 }{ 2 } = f^-1(x) \]

Answer 9

^fixed?

Answer 10

what do i have to fix now

Answer 11

I don't get what 2y/2 has to do with anything but the rest is correct

Answer 12

its suppose to be
2+6 over 2 = 2y over 2

Answer 13

Oh that makes sense