Question

I need some help with math i need someone to tutor me alittle bit so i can understand it better

Answer 1

Well, nobody seems to be on right now that is an expert at math, so i'll tag @Elsa213 or @SmokeyBrown .

Answer 2

ok thx howie

Answer 3

When they come on. And no problem.

Answer 4

I can (depending what it is though)!

Answer 5

Algebra 2

Answer 6

mm what subtopic?

Answer 7

ill put a question down that i dont know how to answer and we can work on it if thats ok

Answer 8

ye sure

Answer 9

Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three, solve for f(g(x)) when x = 2.

2

5

11

33

Im really bad with the whole f(g(x)) stuff

Answer 10

When you are give f(g(x)) You will be plugging in your g(x) into the x-variable of f.

So you have \(\bf{f(x)=x^{2} + 2x +3}\)

For `every x` you plug in your equation of `g(x)`.

Remember that we are told dat `x=2` so you would plug this in for `g(x)`

\(\large\bf{g(x)=\frac{x+4}{3} \rightarrow \color{red}{\frac{2+4}{3}}}\)

Simplify that and plug into each `x` of `f(x)`.

Answer 11

still kinda lost?

Answer 12

yes how can x = g(x) so it would look like f(x) = g(x)2+2g(x) +3?

Answer 13

ye it would!

See you have `f(x)` and `g(x)` it tells you to simplify by `(f(g(x))` meaning for `x` of `f(x) it equals to g(x)`.

Answer 14

ok

Answer 15

so it looks confusing but truly its just the look of it

Answer 16

ye cx there are these variables and complexities of it, but its simple to learn just gotta not look at it as a whole i guess, just in parts ;)

Answer 17

ok

Answer 18

i think i understand it alittle more