Question

Simplify negative 2 and 1 over 6 – negative 7 and 1 over 3.

negative 5 and 1 over 6
negative 9 and 3 over 6
9 and 3 over 6
5 and 1 over 6

Answer 1

What I got from this:

Answer 2

Step one: make everything denominator 6. The red parts are what help you do this.\[-2(\color{red}{\frac{6}{6}})+\frac{1}{6}-(-7)(\color{red}{\frac{6}{6}})+\frac{1}{3}(\color{red}{\frac{2}{2}})\]

Answer 3

Step two: simplify by multiplication (anything without a denominator automatically has 1 at the bottom) and you get:\[\frac{-2}{6}+\frac{1}{6}-(\frac{-42}{6})+\frac{2}{6}\]

Answer 4

Step three: add the numerators, and keep the denominator.\[\frac{-2+1-(-42)+2}{6}\]\[\frac{1-(-42)}{6}=\frac{43}{6}\]

Answer 5

I think they mean:
\[-2 \frac{ 1 }{ 6 } - - 7 \frac{ 1 }{ 3 }\]
\[-2 \frac{ 1 }{ 6 } + 7 \frac{ 1 }{ 3 }\]

Answer 6

Aw

Answer 7

\[-2 = - \frac{ 12 }{ 6 }\]
So,
\[- \frac{ 12 }{ 6 } + - \frac{ 1 }{ 6} = - \frac{ 13 }{ 6 }\]
\[7 = \frac{ 21 }{ 3 }\]
So,
\[\frac{ 21 }{ 3 } + \frac{ 1 }{ 3} = \frac{ 22 }{ 3 }\]
You can only add fractions that have the same denominator so,
\[\frac{ 2 }{ 2 } \times \frac{ 22 }{ 3 } = \frac{ 44 }{ 6}\]
Thus our problem is,
\[-\frac{ 13 }{ 6 } + \frac{ 44 }{ 6 } = \frac{ 31 }{ 6 }\]