Question

Data Interpretation Question..

Answer 1

@Hero @SmokeyBrown

Answer 2

Well, alright, as the water freezes, the density changes from about 920 kg/m^3 to about 1000 kg/m^3.
Using the final value and initial value, you should be able to find the percent change using the equation given

Answer 3

Oh okay thats part of what I had trouble with, they are theoretically just speaking about the value at 0 degrees Celsius

Answer 4

i put 918 because its not exactly on the 920 line, its a better view on the bigger graph

Answer 5

Yeah, that makes sense

Answer 6

Careful about the decimal points. I got 0.09 when I did the calculations.
Then, don't forget to multiply that by 100 to convert the decimal into a percentage.

Answer 7

so 9%

Answer 8

but two sig figs so 9.0%

Answer 9

?

Answer 10

you there?

Answer 11

Oh, yeah, I agree. 9.0% should be right. 8.9%, maybe, but it depends how many decimals you keep when you do the calculations

Answer 12

its wrong :/

Answer 13

@Hero

Answer 14

Why is there information on the side talking about water temperature going from 150 Celsius to 100 Celsius?

Answer 15

Are we talking about water boiling or water freezing that we need to answer about?

Answer 16

freezing

Answer 17

ANd I'm not sure. I think it may just be an introduction

Answer 18

In order to calculate percent change. You need two values. I only see one value mentioned. Zero Degrees Celsius. Is there another part to the problem that you accidentally excluded from the screenshot?

Answer 19

Oh, nevermind lol

Answer 20

I thought she was saying that the graph is not included with the question. I see what the two values are now.

Answer 21

At 0 degrees, the density drops from 1000 to 920

Answer 22

Ok, so the question is about freezing, I overlooked that. The "initial" value would be for water in its liquid state, and the "final" value would be for water in its solid state.
So, if our calculations earlier were correct, your answer should be -9.0%, not 9.0%
Like Hero said, the density decreases, as the water freezes.

Answer 23

The initial value is 1000 and the final value is 920 btw. Plug into the formula and calculate @zarkam21

Answer 24

Or rather ... 920 is the initial value and 1000 is the final value. Sorry. And you're right. Looks like the initial value is less than 920

Answer 25

so -9.0?

Answer 26

bcuz 9.0 didnt work

Answer 27

Let me try to calculate it

Answer 28

Let me try to calculate

Answer 29

I'm getting -8.70

Answer 30

Ugh, still not right. Idk

Answer 31

Hang on. Mixed up the formula

Answer 32

8.70 final answer

Answer 33

If that isn't right. I'm retiring for the night.

Answer 34

It's not :/

Answer 35

Good grief.

Answer 36

I think because the initial value isn't exactly 920

Answer 37

yeah its like 918 or something

Answer 38

its not exactly on the 920 line

Answer 39

No telling. Could be 919 or 917

Answer 40

or maybe its looking for the initial initial value of when water is still liquid to when it turns into ice. "Calculate the percent change in density that occurs when liquid water freezes to ice at 0 ∘C given that"

Answer 41

No, it's pretty clear the values apply to the Zero Degree Celsius condition.

Answer 42

Mmm

Answer 43

What do the available hints say?

Answer 44

...

Answer 45

SOrry was taking me a minute to take screenshots

Answer 46

What happens if you scroll your cursor over the graph? Does it display any values?

Answer 47

no nothing

Answer 48

There is no way to say for certain what the initial value is.

Answer 49

lets try 919 just for the last of it

Answer 50

You have two attempts remaining. try 918 and 919

Answer 51

So 1000-919/919*100% = 0.08 = 8%

Answer 52

Will they reveal the correct answer after you've run out of attempts? This is why I don't help with chem questions.

Answer 53

Ohhhhhhhhhhhhhh !!

Answer 54

I'm getting 8.8 for that calculation

Answer 55

In the hints section, you can submit the density in kilograms per cubic meter as an integer.

Answer 56

This should solve our issue

Answer 57

so we said the initial was 919 let me try that

Answer 58

Curious eyes await the truth value

Answer 59

Could be anything from 917 to 919. It's def not 920

Answer 60

This is what it is saying

Answer 61

Try 918 and 917

Answer 62

well how do we calculate the density of a curve

Answer 63

All wrong

Answer 64

Okay. I'm out of the game then. Guess I don't know what they're asking. Never ask me a chem question again.

Answer 65

Lol okay.

Answer 66

@Shadow

Answer 67

PLease help.

Answer 68

Do they give you the answer if you run out of attempts?

Answer 69

Yes, but I lose all points :/ I think @Vocaloid IS BUSY

Answer 70

otherwise she would havebeen able to help

Answer 71

I'm curious as to what the answer is. There's voca now.

Answer 72

No, she said she is busy

Answer 73

I don't think she would come here if she did not intend to provide some assistance.

Answer 74

Okay genius.

Answer 75

hm. just a hypothesis based on an initial glance, but if they want the density of water as it freezes, perhaps you would start from the top of the 0 celcius region (so closer to the 1000 kg/m^3 region?)

Answer 76

I haven't read the entire thread so sorry if you guys already tried that >>

Answer 77

Tried that with values 1000 and 920

Answer 78

rip

Answer 79

BTW @zarkam21 did you already confirm that 920 is definitely not the initial value?

Answer 80

JUst did right now and it is not

Answer 81

Okay, just checkin'

Answer 82

I got the answer. I ran out of attempts its -8.0

Answer 83

Hmm

Answer 84

Yep, no more chem questions for me. You had it and I discouraged you from putting that.

Answer 85

I mis-interpreted the significant digits thing.

Answer 86

But did they say what the initial value was?

Answer 87

No, it just siad The density of water decreases by about 8.3% as it changes from a liquid to a solid. Since ice is less dense than liquid water, it floats.

Answer 88

I see.

Answer 89

would this be the same idea?

Answer 90

Now they want volume, but I'm going to withdraw from helping further with this question. Try MHB or Quora.

Answer 91

OKay thanks for the help =) I appreciate the help