Solve for x. 38(2x+16)−2=13 Enter your answer in the box
is 38 supposed to be a fraction or naw?
yes is it
So it is... \(\large\bf{\frac{3}{8} (2x+16)-2=13}\) ?
^^
yes
Okay. First you need to distribute the \(\bf\frac{3}{8}\) into the parenthesis. \(\Large\bf{\frac{3}{8} (2x+16) ~~\rightarrow ~~~~(\frac{3}{8} \times 2x)+(\frac{3}{8} \times 16)}\) What does that simplify to?
thats what i dont know i need help figuring it out
I know im telling you how. You distribute the fraction into the parenthesis. What does \(\large\bf{\frac{3}{8} \times 2x}\) equal?
4/16
Not quite. \(\large\bf{\frac{3}{8} \times 2x ~~~ \rightarrow \color{red}{\frac{3 \times 2}{8}x}}\) What does that simplify to?
6/8
correct. now this can be simplified further. \(\large\bf{\frac{6}{8} \rightarrow \frac{3}{4}}\) by division of 2. Now we distribute the fraction to 16. \(\Large\bf{\frac{3}{8} \times 16 \rightarrow \frac{3 \times 16}{8}}\)
48/8
Okie now simplify that
6
Correct. So our distributed parenthesis is simplified to: \(\Large\bf{\frac{3}{8}(2x+16) \rightarrow \color{red}{\frac{3}{4}x+6}}\) So we have: \(\Large\bf{\frac{3}{4}x+6-2=13}\) Got it?
yayyyyy thank you so so so much
not done yet
still have to simplify further
ok what do i do now
Now you need to subtract 6 and 2. \(\Large\bf{\frac{3}{4}x+\color{red}{6-2} ~~\rightarrow \frac{3}{4}+4=13}\)
3/4x*
4
Now you need to get the variable to one side. You see that `4` is being added to `3/4x` this means you need to `SUBTRACT` `4` from both sides to get it to one side. \(\Large\bf{\frac{3}{4}x + 4 \color{red}{-4} = 13 \color {red}{-4}}\) What does that simplify to?
9
Correct. So we now have: \(\Large\bf{\frac{3}{4}x=9}\) Now you need to apply the fraction to the other side. So you divide the fraction to get x to itself. \(\huge\bf{\frac{\frac{3}{4}}{\color{red}{\frac{3}{4}}}x=\frac{9}{\color{red}{\frac{3}{4}}}}\) What does x equal?
ummmm
To simplify by fraction you follow by: \(\large\bf{\frac{a}{\frac{b}{c}}=\frac{a \times c}{b}}\) So: \(\huge\bf{x=\frac{9 \times 4}{3}}\)
32/3?
12
x=12
Correct! So `x=12` cx
nice job!
will you be my tutor
cx uh well if you ever need help just dm me >.< i actually have to go right now ;-;
ok thank you
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