Question

calc help 4 questions

Answer 1

@Tranquility

Answer 2

still typing lol?

Answer 3

First find the derivative of f'(x)
For this you should watch this video till time 6.10 as I cannot explain through writing https://youtu.be/QqF3i1pnyzU

So now you got the formula as f'(x)=nx^n-1
So for you question for x^2
n=2
And first 5x n=1
Apply in formula
f'(x)=2x^2-1 + 1*5x^1-1
f'(x)=2x +5
So as they said x=4
Put 4 in 2(x)+5
It's
f'(4)=2(4)+5
f'(x)=13

Answer 4

I thought so lol could you help with 3 more?

Answer 5

Yep it would be great (:

Answer 6

-3?

Answer 7

Yes

Answer 8

really why?

Answer 9

when I did difference quotient it was -3/1-h

Answer 10

they all appear to be symmetric quotients

Answer 11

f'(x)=3/x
That is same as f'(x)=3x^-1
So in this n=-1
Put in the formula
f'(x)=nx^n-1
That is= -1*3x^-1-1
That is=-3*x^-2
That is same as -3/x^2
Put -1 in place of x
-3/(-1)^2
-3/1=-3

Answer 12

this one is 0?

Answer 13

I'm fanning you lol so if I need further help I know who to tag lol

Answer 14

Hahaha

Answer 15

Wait m solving

Answer 16

Does not exist

Answer 17

D

Answer 18

just curious why is that?

Answer 19

https://youtu.be/H-ybCx8gt-8

Answer 20

Now the formula you got is (derivative of outside leaving the inside as it is) *(derivative of inside)

Answer 21

it looks like a cusp but could be a corner
I'm thinking more cusp because it bends slightly

Answer 22

for the last question I say cusp

Answer 23

n=1/5
Take the derivative of outside it is 1/5(x+1)^(1/5)-1

That is 1/5(x+1)^-4/5

Put value of x=-1
1/5(0)^-4/5
And O^-4/5 is math error solve on calculator so
Derivative of this does not exist

Answer 24

okay cool

Answer 25

Did you understand?

Answer 26

yes I did

Answer 27

Okay great

Answer 28

is the last one cusp?

Answer 29

just curious college student?

Answer 30

Yes college student and you?

Answer 31

I would say cusp because of the graph ty though and senior in hs lol

Answer 32

K (:

Answer 33

Sorry I don't know the answer for that question

Answer 34

it's okay