kaylak:

need calc checked and finished

3 months ago
kaylak:

@Vocaloid

3 months ago
kaylak:
3 months ago

kaylak:
3 months ago

kaylak:
3 months ago

SmokeyBrown:

So, since the derivative of the function f(x) has a value of 1/2 when x=2, we know that f(x) has a slope of 1/2 when x=2. The line Normal to f(x) would be perpendicular to f(x). The slope of the perpendicular line must have be the negative reciprocal of the original line. And the negative reciprocal of 1/2 is -2. So, our answer must have a slope of -2. The only choice with a slope of -2 is A, so our answer should be A.

3 months ago
kaylak:

ty @Vocaloid do you agree?

3 months ago
Vocaloid:

yeah

3 months ago
kaylak:

can you help with more?

3 months ago
kaylak:
3 months ago

kaylak:
3 months ago

Vocaloid:

uh as far as I know the symmetric difference quotient is [ f(a+h) - f(a-h) ] / 2 where a is the x-value being evaluated, and h is 0.5 as given in the problem

3 months ago
Vocaloid:

so [ f(2+0.5) - f(2-0.5) ] / 2 disclaimer: I'm not entirely familiar with this concept but that's what I got from the internet.

3 months ago
kaylak:
3 months ago

SmokeyBrown:

|dw:1539580582859:dw| I think the graph of the derivative should look something like this. At first, the original is increasing, so the derivative should start at a positive value. As the original function approaches -1, the slope decreases to 0, then decreases further to about -1. From there, the slope increases to its original value once again as the graph begins ascending

3 months ago
kaylak:
3 months ago

SmokeyBrown:

Hm, I honestly don't know anything about that one, sorry

3 months ago
kittybasil:

@photonics

3 months ago
photonics:

Hm, I honestly don't know anything about that one, sorry

3 months ago