kaylak:

need calc checked and finished

1 month ago
kaylak:

@Vocaloid

1 month ago
kaylak:

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1 month ago
kaylak:

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1 month ago
kaylak:

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1 month ago
SmokeyBrown:

So, since the derivative of the function f(x) has a value of 1/2 when x=2, we know that f(x) has a slope of 1/2 when x=2. The line Normal to f(x) would be perpendicular to f(x). The slope of the perpendicular line must have be the negative reciprocal of the original line. And the negative reciprocal of 1/2 is -2. So, our answer must have a slope of -2. The only choice with a slope of -2 is A, so our answer should be A.

1 month ago
kaylak:

ty @Vocaloid do you agree?

1 month ago
Vocaloid:

yeah

1 month ago
kaylak:

can you help with more?

1 month ago
kaylak:

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1 month ago
kaylak:

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1 month ago
Vocaloid:

uh as far as I know the symmetric difference quotient is [ f(a+h) - f(a-h) ] / 2 where a is the x-value being evaluated, and h is 0.5 as given in the problem

1 month ago
Vocaloid:

so [ f(2+0.5) - f(2-0.5) ] / 2 disclaimer: I'm not entirely familiar with this concept but that's what I got from the internet.

1 month ago
kaylak:

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1 month ago
SmokeyBrown:

|dw:1539580582859:dw| I think the graph of the derivative should look something like this. At first, the original is increasing, so the derivative should start at a positive value. As the original function approaches -1, the slope decreases to 0, then decreases further to about -1. From there, the slope increases to its original value once again as the graph begins ascending

1 month ago
kaylak:

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1 month ago
SmokeyBrown:

Hm, I honestly don't know anything about that one, sorry

1 month ago
kittybasil:

@photonics

1 month ago
photonics:

Hm, I honestly don't know anything about that one, sorry

1 month ago
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