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Mathematics 16 Online
8bithelix:

Math help please, will medal- 1. http://prntscr.com/l6w2ba 2.http://prntscr.com/l7575c

8bithelix:

@Angle

563blackghost:

What did you get for the others?

8bithelix:

as far as question 1?

563blackghost:

ye for question 1

8bithelix:

give me a moment.

8bithelix:

first pair is AAA(Or possibly) HL Second pair-SSS? Third pair-NA Fourth pair-SSS

8bithelix:

second pair is wrong, dont mind that. ill try to correct it in a second

8bithelix:

second pair- fifth pair- SAS Sixth pair- ??? seventh pair-AAS

8bithelix:

second might be SAS

563blackghost:

AAA can not be used.

8bithelix:

thats the answer shadow came up with. so hmm

563blackghost:

hrm i thought AAA and SSA couldnt be used, if shadow said otherwise then go with what he said.

8bithelix:

but the question is can HL be used in any of this

563blackghost:

HL can be used for the 2nd one.

8bithelix:

i see why now so HL for second.

563blackghost:

mhm

563blackghost:

4th one is correct, 5th is incorrect you would define it by AAS theorem. you know a 2nd angle by the vertical angle theorem meaning `angle o = angle o`.

8bithelix:

hm. ok then

563blackghost:

make sure to mark the vertical angles, it says so in your question.

563blackghost:

The 6th pair is defined by SAS Theorem. The triangles are alike but one is simply reflected.

563blackghost:

7th one, you are correct on there being 2 congruent angles and one congruent side pair but it would not be AAS, look how the angles and side is. The side is contained within the congruent angles, this means it is defined by `ASA`

8bithelix:

i assume the third one is correct because there is no given information whatsoever

563blackghost:

hrm

563blackghost:

The 1st one and the 3rd one confuse me, cause youll assume by AAA but AAA is not a rule for proving congruency.

8bithelix:

its not AAA

8bithelix:

for the first

563blackghost:

oh what did you put?

8bithelix:

i feel the most logical answer for the first is ASA

8bithelix:

wait wait

8bithelix:

SAS

563blackghost:

but no side is determined congruent. I would go with NA do you agree @dude ?

8bithelix:

actually i can see it being NA as well as 3

8bithelix:

so ima just look at 3 and tell you why from my own view, it might be wrong but w/e i tried

563blackghost:

i would say NA for the 1st one and the 3rd one too.

8bithelix:

there are 3 angles on 3, AAA cant be used what so ever

563blackghost:

mhm

8bithelix:

basically no sides to it

8bithelix:

1 is tough because looking at it, it could be HL but on the top it has an angle

8bithelix:

in order for the first pair to be correct you would either have to remove the 90 degree sign from it alltogether and then it possibly could be something like ASA

8bithelix:

just by the angle being there it blows it completely out of proportion

563blackghost:

HL can only be used unless the hypotenuse is defined as congruent to the corresponding hypotenuse.

8bithelix:

so here is what it looks like http://prntscr.com/l76ziu

8bithelix:

i can edit the images with the angles and sides later, i have other math work to do.

563blackghost:

dat looks right

563blackghost:

For your 2nd problem the 1st reason is given, because you are told this problem.

563blackghost:

now you follow by PEMDAS, you need to simplify the paranthesis so how would you do this?

8bithelix:

by using addition properity of equality?

563blackghost:

not quiet, you have \(\bf{6x=3(x+4)}\) you need to first deal wid da parenthesis BUT you see that 3 is being multipled by the parenthesis, so you have to deal wid da multiplication first. What property is this?

8bithelix:

multiplication property of equality

563blackghost:

mm your in the right direction, we have to apply the 3 into the parenthesis, so we distribute it. We follow by `Distributive Property of Equality`.

8bithelix:

Ah

563blackghost:

`Distributive Property of Equality` goes by: \(\large\bf{a(b+c)=ab+ac}\)

563blackghost:

Now we need to get the variable to one side, so in your 3rd statment you seem to be subtracting 3x from each side, what property is this?

8bithelix:

subtraction property of equality

563blackghost:

correct. now what would you label the 4th step? nothing seems to be done only that it simplified. So how would you label the reasoning?

8bithelix:

divide 3 on each side?

8bithelix:

wait

8bithelix:

division property of equality

563blackghost:

mm thats the 5th one

563blackghost:

4 and 6 would just be defined as `simplify` because the step before you already stated what you are doing.

8bithelix:

oh.

8bithelix:

i get it now.

8bithelix:

i have other questions that im doing so would you mind checking them to see if they are exceptional when im done with them?

563blackghost:

mm sure

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