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zarkam21:
How many mL of water are required to make up a 1.87M solution if you start with 0.791 moles of Ca(NO3)2
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zarkam21:
@Vocaloid
Vocaloid:
molarity = moles solute/L solvent 1.87M = 0.791 moles of Ca(NO3)2 / L solvent solve for L solvent, then multiply by 1000 to convert to mL
zarkam21:
2364
Vocaloid:
hm 1.87 = 0.791/x solving for x gives me 0.422995L, then multiplying gives 423mL
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