zarkam21:

Draw the lewis dot diagram for the following atoms F He S

2 months ago
Vocaloid:

any ideas on F? based on its location on the ptable how many valence electrons do you think it has? as a reminder these are neutral atoms, not ions

2 months ago
zarkam21:

7

2 months ago
Vocaloid:

awesome, so you'd draw 7 electrons (3 pairs of 2, plus 1 leftover)

2 months ago
Vocaloid:

thoughts on helium?

2 months ago
zarkam21:

2

2 months ago
Vocaloid:

good helium is a special case, it only has a 1s orbital so the electrons have to be paired up

2 months ago
Vocaloid:

thoughts on sulfur?

2 months ago
zarkam21:

6

2 months ago
Vocaloid:

good sulfur follows the normal rule for pairing, fill up 4 electrons separately then pair up the last 2

2 months ago
Vocaloid:

|dw:1540096403486:dw|

2 months ago
zarkam21:

CH4

2 months ago
Vocaloid:

any ideas? have you tried adding up all the valance electrons for 1 carbon 4 hydrogens?

2 months ago
zarkam21:

|dw:1540096455806:dw|

2 months ago
Vocaloid:

perfect

2 months ago
zarkam21:

But isn't there dots

2 months ago
Vocaloid:

there are no free electrons so there shouldn't be any

2 months ago
Vocaloid:

this is a covalent compound so all the bonds involved shared electrons, represented by the lines

2 months ago
zarkam21:

Sel2

2 months ago
Vocaloid:

thoughts? any attempts to add up the valence electrons?

2 months ago
Vocaloid:

well, anyway, selenium has 4 valence e's and each iodine has 7, so 6 + 7 + 7 = 20, divide by 2 to get 10 electron pairs so set up your compound where Se is in the middle, and I is bonded to the left and right, and fill up enough lone pairs so that the whole compound has 10 electron pairs total

2 months ago
zarkam21:

|dw:1540102685656:dw|

2 months ago
Vocaloid:

that's only five pairs, so you gotta fill up the iodine atoms completely to get 10 total pairs

2 months ago
Vocaloid:

10 total pairs = 20 total electrons

2 months ago
zarkam21:

|dw:1540102838122:dw|

2 months ago
Vocaloid:

almost just one more bond on the first SeI

2 months ago
Vocaloid:

also when you make a double bond you have to erase an electron pair

2 months ago
Vocaloid:

... wait

2 months ago
zarkam21:

but thats still 16 :(

2 months ago
Vocaloid:

oh, of course, selenium has an expanded octet so it can actually take more than 8, so put the last electrons on the selenium atom itself

2 months ago
Vocaloid:

|dw:1540103171322:dw|

2 months ago
zarkam21:

I3^-

2 months ago
Vocaloid:

well, each iodine gives 7, so 3*7, then you gotta add 1 because we have a -1 charge, so 22 electrons or 11 pairs

2 months ago
Vocaloid:

as a hint this one only has single bonds

2 months ago
zarkam21:

|dw:1540103405053:dw|

2 months ago
Vocaloid:

yeah that should be it, just two things 1. the pair of electrons on the right side shouldn't be in between the bond, they need to be off to the right side 2. since this is an ion you also need to draw a set of brackets around the whole thing, and write the charge at the top right

2 months ago
zarkam21:

|dw:1540103565219:dw|

2 months ago
Vocaloid:

|dw:1540103559925:dw|

2 months ago
Vocaloid:

yup good

2 months ago
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