Check
well first off it's the same trait (color) so you should only be using one type of allele (so only use A alleles not b-alleles) assuming black is dominant and white is recessive, the grey sheep/ram should both be Aa (since they have one black allele and one white allele --> grey) so gray sheep = Aa and black ram = AA, show the punnet square between these two
A) should be incomplete dominance not co-dominance
because neither allele is dominant
incomplete dominance = produces a blend of the two traits (so black + white --> gray) co-dominance = produces both traits at once (so black + white = a black and white sheep)
black is still dominant but it's called incomplete dominance because it doesn't completely mask the recessive white allele
still there? it's just a 2x2 cross between Aa * AA
Yeah lol I'm just writing as I go
only one trait so it just works as a regular 2x2 punnet square |dw:1540276207916:dw|
|dw:1540276213364:dw|
so each offspring should only have two letter a's
I thought they were supposed to be the same on the top and left
you have a gray sheep and a black ram these don't have the same genotype so one of them is AA and the other is Aa
okay I got that now for the percentages it would be 2/4 will be black
and 2/4 will be grey
yes as percentages, 50% and 50%
and whitr as zero
yes
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