I think the answer is 24 units
What is the area of a rectangle with vertices at (−6, 3) , (−3, 6) , (1, 2) , and (−2, −1) ?

Enter your answer in the box. Do not round any side lengths.

Question

I think the answer is 24 units 
What is the area of a rectangle with vertices at ​ (−6, 3) ​, ​ (−3, 6) ​ , (1, 2) , and (−2, −1) ?

Enter your answer in the box. Do not round any side lengths.

CC12 · Answer

@Eiwoh2 can you help

Eiwoh2 · Answer

Sorry, i can't really help with this type of mathematics. I'll get @dude here to help ye. He's a boss. XD

CC12 · Answer

Thank you

dude · Answer

D: I’m in mobile so I can’t type all the math but find the distance between 2 points

Do you know the distance formula?

CC12 · Answer

(-6,3) and (-3,6)
d(A,B)=3√2 ≈ 4.2426

CC12 · Answer

@dude

dude · Answer

Hmm, I got a different thing, what did you do?

CC12 · Answer

$$d(A,B)=\sqrt{(-3-(-6))}^2+(6-3)^2$$

dude · Answer

Ah, all of it goes inside the square root

dude · Answer

$\sqrt{(6-3)^2+(-3--6)^2}$

CC12 · Answer

9 units

CC12 · Answer

sorry it takes me a little longer to figure out the problem i have trouble with math

dude · Answer

Uh, its okay but its not 9

$\sqrt{(6-3)^2+(-3+6)^2}\
\sqrt{(3)^2+(3)^2}\
\sqrt{9+9}\
\sqrt(18)\approx 4.24$

dude · Answer

Now find the distance between (-3,6), (1,2)

CC12 · Answer

$$\sqrt{1-(-3))^2+(2-6)^2}$$ =5.65

CC12 · Answer

$$\sqrt{16+16}$$ $$\sqrt[4]{2}$$

dude · Answer

Careful, you want to be careful on parenthesis placement

$\sqrt{(2-6)^2+(1--3)^2}\
\sqrt{(-4)^2+(4)^2}\
\sqrt{16+16}\
\sqrt{32}\approx 5.65$

dude · Answer

Area is length times width, so multiply them

CC12 · Answer

23.956