What is the measure of PQ?
In circle T, ∠PTQ ≅ ∠RTS.
cant upload picture
|dw:1540915764025:dw| is it like this?
You can press the pencil-button on the top-right of my drawing to draw on it.
Oh okay. So you see how there are 2 triangles in there? |dw:1540915914346:dw|
yea
The 2 triangles are the same (or congruent). Because the angles from the middle are the same. And since it's a circle, all the sides of the triangle are the same. (The radius doesn't change).
What is the measure of ? 24° 33° 48° 66°
What is the measure of what? your question didn't say what angle.
pq
Oh that's the same as SR. Remember how the 2 triangles are the same? It's also 66 then.
Which kind of triangle must triangle XYZ be? an equilateral triangle an isosceles triangle a scalene triangle a right triangle
Hmm.. It looks like XY and YZ have the same lengths so it'll be an isosceles.
A point is on a circle if the distance from the center of the circle to the point is equal to the area. circumference. radius. diameter.
|dw:1540916727074:dw| Do you know what that red line is called?
radius
Yeah. That's what the question was describing.
What is the length of the radius, r? 8 units 10 units 12 units 16 units
?
Sorry uh...I'm still thinking about it
take your time
I'm going to make one assumption. "KL is tangent to circle J." Otherwise I don't think it's possible to solve this.
yea it is tangent to J
|dw:1540917166085:dw| let me look at this a little more
GOT IT. So you know what the Pythagorean theorem is right?
know of it
\[(Leg)^2 + (Leg)^2 = (Hypotenuse)^2\] If we use it here: \[(r)^2 + (24)^2 = (r+16)^2\]
So if we simplify that it becomes \[r^2 + 24^2 = r^2 + (2)(16)(r) + 16^2\] and that becomes \[24^2 =32r + 16^2\]
Are you able to solve for 'r' from here? or would you like me to help.
yea
its 10
Welp. There's your answer.
In the diagram of circle C, m∠VWX is 43°. What is m? 39° 41° 78° 82°
would i do the same for this
No since none of them are tangents. Tangents make a right-angle. And you can only use pythagorean theorem for right-angle triangles.
Okay wait, where is 'm' at?
there is no m
|dw:1540917711896:dw| So uh what are we looking for?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @noblelove42 In the diagram of circle C, m∠VWX is 43°. What is m? 39° 41° 78° 82° \(\color{#0cbb34}{\text{End of Quote}}\) This is what you asked
What is mvx?
oh
|dw:1540917938014:dw|
Sorry I messed up xd, anyways there's the formula. |dw:1540917983781:dw|
Can you solve for VX in this equation: \[43 = \frac{125-VX}{2}\]
82?
I got 39. 43 x 2 = 125 - VX 86 = 125 - VX VX = 125 - 86 VX = 39
ok i get it
In circle O, what is m∠MAJ?
I actually don't know how to solve this without assuming A is right underneath O. xd. Are there answer choies?
no answer choices
Yeah shoot. i can't help anymore sorry.
@ThisGirlPretty Are you able to help with this question?
What is the area of the sector that is not shaded? 12 24 120 144
My brain is burned out. You know the area of a circle right? In here it would be 12^2 * pi Which is 144pi. Then you know that a circle is 360 degrees right? And you're only trying to find (360-60) degrees of it. That's 300/360 or 5/6 of the circle. So you divide 144pi by 6 and multiply it by 5. 5*144pi/6 = 120pi.
I can't help anymore. I'm gonna suffer some mental trauma.
help tomorrow ?
thank you
If you get on maybe xd.
what is that
questions that need to be answered ?
?
The measure of central angle ABC is radians. What is the area of the shaded sector?
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