Question

Given the following three mRNA sequences, determine which two code for the same protein.
mRNA #1:
Transcript: AGU UUA GCA ACG AGA UCA
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mRNA #2:
Transcript: UCG CUA GCG ACC AGU UCA
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mRNA #3:
Transcript: AGC CUC GCC ACU CGU AGU
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Answer 1

unfortunately this is very tedious but I can show you how it's done using the first example

Answer 2

using MRNA1:

AGU --> first letter is A, so we go to the A row in the chart
second letter is G --> so the 4th column
then last letter is U --> Ser is the amino acid you want
then repeat with the other codons

Answer 3

you need to know this method for exams but as a time-saver there is software that will accomplish this for you

https://skaminsky115.github.io/nac/DNA-mRNA-Protein_Converter.html

Answer 4

still there? any attempts on the next codon, UUA?

Answer 5

sorry, my wifi cut out.
yes, i am familiar with this method but the way it was worded confused me a little.
@Vocaloid

Answer 6

UUA-leu
GCA-ala
ACG-thr
AGA-arg
UCA-ser

Answer 7

yup good, then you gotta check the others, too unfortunately

Answer 8

yeah, i did them

Answer 9

one thing i dont understand though is the point mutation, substitution, frameshift, insertion, or deletion

Answer 10

if theres a stop in an amino acid do i not continue writing down the rest of the amino acids?

Answer 11

yes

if you get a stop codon, that's where the protein will detach

Answer 12

ok

Answer 13

thanks so much for your help!
sorry for the late reply, again