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A serving of Cheez-Its releases 130 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy were transferred to 2.5 kg of water at 27°C ,what would the final temperature be?
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Ooh, Cheez its. I like those. Anyway, what can you understand from this question?
q = mc * deltaT you are given q from the cheetos, so plug that in for q, then for the other variables, use water's mass, water's specific heat, to find the delta T for water
cheez-its, whatever
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