Question

Can anyone solve this for me?

Answer 1

\[a_{n} = a_{1} r^{(n-1)}\]
The nth term of the sequence is equal to the first term of the sequence multiplied by the common ratio to the power of nth's position minus one.

Answer 2

\[r = \frac{ a_{2} }{ a_{1} }\]
The common ratio is equal to the second term of the series divided by the first term of the series.

Answer 3

\[r = \frac{ -15 }{ 3 } = -5\]

Answer 4

To show you the formula works...
\[a_{2} = 3(-5^{2-1}) \rightarrow a_{2} = 3(-5^{1}) \rightarrow a_{2} = -15\]

Answer 5

You just have to do the same thing but for the 6th position.

Answer 6

@ILoveXXXTENTACION Do you understand how to use the formula?

Answer 7

sure, when i figure it out, ill tell u what i think is the answer, k?

Answer 8

For sure.

Answer 9

Want me to do a third example or you do you think you can figure it out?

Answer 10

ill try to figure it out lol

Answer 11

Sounds good.