Can someone plz solve this for me?

Question

ILoveXXXTENTACION · Answer

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Shadow · Answer

This is basically the same question as the one you posted last night. Were you able to solve that one?

ILoveXXXTENTACION · Answer

no, hold on that is the wrong one

Shadow · Answer

Hmm, still the same concept

ILoveXXXTENTACION · Answer

but can u just give my the answer, cuz its do rn

Shadow · Answer

$$a_{n} = a_{1} r^{(n - 1)}$$
This is how we find the nth term. In this case, the 6th term, of the geometric sequence.
$$r = \frac{ a_{2} }{ a_{1} }$$
This is how we find the common ratio between each terms so that we can solve for the nth term.

$$r = \frac{ a_{2} }{ a_{1} } \rightarrow r = \frac{ -25 }{ 5 } \rightarrow r = -5$$
$$a_{6} = 5(-5^{(6-1)})$$

ILoveXXXTENTACION · Answer

so what is the answer?

Shadow · Answer

What's 6-1

ILoveXXXTENTACION · Answer

is 5

Shadow · Answer

So take -5 to the 5th power then multiply that by 5

Shadow · Answer

$$a_{6} = 5(-5^{(6-1)})$$
That is basically what this is saying.

Shadow · Answer

I wish you had taken the time to actually learn this concept. It's actually quite simple.

Anyway, the rest just takes a calculator.

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