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Mathematics 15 Online
kaylak:

calc help

jhonyy9:

???

kaylak:

need 5 7 and 8

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kaylak:

@jhonyy9

jhonyy9:

hi

jhonyy9:

5. given a right triangle with length of hypothenuse = 10 using pythagora you know that 10^2 = x^2 +y^2 and you know that area of a triangle equal base time height divide 2 so in this case area = x time y divide 2 100 = x^2 +y^2 A = x*y/2 from these you need calcule the values of x and y for what the area will be maximum hope helped

kaylak:

okay so square root 50

kaylak:

that's the answer my teacher gave me

kaylak:

for both x and y

kaylak:

@Hero

kaylak:

question 7?

jhonyy9:

but do you understand why sqrt50 ?

kaylak:

yes about 7.1 is 50 +50=100

kaylak:

7.1^2

jhonyy9:

bc. 100 = x^2 +y^2 100 = (sqrt50)^2 +(sqrt50)^2 100 = 50 +50

kaylak:

yes

jhonyy9:

yes and you need to know again that area will be maxim than x=y ok.?

kaylak:

I know don't feel like typing everything I have but I got the answer

jhonyy9:

for 7. you need to know the formula of perimeter of a cyrcle

kaylak:

2pir

jhonyy9:

yes so given that the perimeter increasing 3 m/s what result from this ?

jhonyy9:

us what you know 2pir increasing 3 m/s from this result that r increasing 3/(2pi) m/s do you understand it ?

kaylak:

@Vocaloid

kaylak:

need 7 and 8

kaylak:

@Shadow

kaylak:

@Ultrilliam

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