calc help
???
need 5 7 and 8
@jhonyy9
hi
5. given a right triangle with length of hypothenuse = 10 using pythagora you know that 10^2 = x^2 +y^2 and you know that area of a triangle equal base time height divide 2 so in this case area = x time y divide 2 100 = x^2 +y^2 A = x*y/2 from these you need calcule the values of x and y for what the area will be maximum hope helped
okay so square root 50
that's the answer my teacher gave me
for both x and y
@Hero
question 7?
but do you understand why sqrt50 ?
yes about 7.1 is 50 +50=100
7.1^2
bc. 100 = x^2 +y^2 100 = (sqrt50)^2 +(sqrt50)^2 100 = 50 +50
yes
yes and you need to know again that area will be maxim than x=y ok.?
I know don't feel like typing everything I have but I got the answer
for 7. you need to know the formula of perimeter of a cyrcle
2pir
yes so given that the perimeter increasing 3 m/s what result from this ?
us what you know 2pir increasing 3 m/s from this result that r increasing 3/(2pi) m/s do you understand it ?
@Vocaloid
need 7 and 8
@Shadow
@Ultrilliam
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