calc help @vocaloid
7 and 8 plz
for 7 you just need to take the derivative of the perimeter equation wrt t and plug in dp/dt to solve for dr/dt for 8 solve for c where f'(c) = 0 you will need to take the derivative of the function
@Shadow I got the derivative but what do I do next?
You are given dp/dt and r Take the derivative, plug in dp/dt and r, solve for dr/dt
perimeter of a circle = 2pi*r dp/dt = 2pi * dr/dt
for dr/dt do I plug in radius/time?
could you help me get these solved before 2. I have a meeting today
8. I have the derivative 2/(x+1)^2
@v
@Vocaloid
@Ultrilliam
@Angle
which one are we still stuck on?
7 and 8
do you see them? or do I need to repost
I see them what do you have so far? for 7, you have the equation for the perimeter of the circle which is P = 2*pi*r and vocaloid has pointed out that taking the derivative in terms of time gives dp/dt = 2pi * dr/dt
I have that part do I plug in or what do I do next
[honestly it's been a while since I have done a related rates problem] I think you are given that the "rate of change for the perimeter in terms of time" (i.e. dp/dt) = 3 so you plug in dp/dt = 3 and get dr/dt
okay so .48 makes sense
8?
we start off with finding f(4) = ? and f(5) = ?
I have the derivative 2/(x+1)^2
I would think so yes
ok ok so for this problem we want to find the slope between f(4) and f(5) then find the point between 4 and 5 that has the same slope so first step is to find the slope between f(4) and f(5)
once you find that slope, you set the derivative equal to that number and solve for x so 2/(x+1)^2 = slope and solve for x
do you thinl I should graph it to find F(4) and 5
I think you can just plug in? like f(4) = (4-1)/(4+1) = 3/5 f(5) = (5-1)/(5+1) = 4/6 = 2/3 so slope = (y2 - y1) / (x2 - x1) = \(= \frac{(2/3) - (3/5)}{5-4}\) = ?
got it ty
4.48
perfect :)
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