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Mathematics 49 Online
8bithelix:

2 questions please need help ASAP: 1.http://prntscr.com/lskdtp 2.http://prntscr.com/lske2d

8bithelix:

@AP

8bithelix:

@dude

photonics:

4 top left: the three altitudes of a triangle intersect at the orthocenter 4 top right: the three medians of a triangle intersect at the centroid 4 bottom left: the three perpendicular bisectors of a triangle intersect at the circumcenter 4 bottom right: the three angle bisectors of a triangle intersect at the incenter

AP:

2.) EG and BC are parallel in that they both share a slope of -1/3 EG is 1/2 of BC because: • Point B is at (4,-2) and point C is at (-5,1) • The distance from point B to point C is as follows: \[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y_{1})^2}\] \[d=\sqrt{(-5 - 4)^2 + (1-(-2))^2}\] \[d=\sqrt{(-9)^2+(1)^2}\] \[d=\sqrt{81+1}\] \[d=\sqrt{82}\] \[d=9.05538513814 ~units\] • The distance from point E to point G should be 1/2 of the distance from point B to point C (in other words, 1/2 of 9.05538513814 units) • Point E is at (-2, 3) and point G is at (2.5, 1.5) • The distance from point E to point G is as follows: \[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y_{1})^2}\] \[d=\sqrt{(2.5 - (-2))^2+(1.5-3)^2}\] \[d=\sqrt{(4.5)^2+(-1.5)^2}\] \[d=\sqrt{(20.25 + 2.25)}\] \[d=\sqrt{22.5}\] \[d=4.74341649025\] • 1/2 of 9.05538513814 is 4.74341649025 • Therefore, EG is 1/2 of BC.

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