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eviant:
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eviant:
eviant:
@Zepdrix I know it's not the 1st one, since that just equals 5
eviant:
the 2nd one: 2=\[\sqrt{-2-2-5}\]
Zepdrix:
notice that we have x-2 under the root, so plugging in anything less than 2 is gonna leave us with a negative under the square root, which is no bueno. \(\large\rm \sqrt{-5-2}=\sqrt{-7}\) \(\large\rm \sqrt{-2-2}=\sqrt{-4}\) \(\large\rm \sqrt{1-2}=\sqrt{-1}\) We can't take the square root of a negative, these x values will all fail to give us a point for the function.
Zepdrix:
But x=3 is larger than 2, yay! Try that one :D
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