Question

http://prntscr.com/lvrxck

Answer 1

@Vocaloid

Answer 2

try factoring the denominators of choices B and C

Answer 3

Can you show me one of them and I do the other?

Answer 4

you should look for the answer choice that makes the denominator 0 when you plug in either x = 2 or x = 4

Answer 5

for choice B try to find two integers that multiply to 8 and add to 6
for choice C try to find two integers that multiply to 8 and add to -6

Answer 6

Choice B: (x+2)(x+4)

Choice C: (x-4)(x-2)

Answer 7

thats what comes out when you factor the denominators

Answer 8

good
so which choice makes the denominator 0 for x = 2 and x = 4?

Answer 9

wait so we plug in

Answer 10

so like (2+2)(4+4)

Answer 11

and (2-4)(4-2)

Answer 12

no, you should choose the same x value at a time

so start by plugging in x = 2 for all x's, then after that start over and plug in x = 4

Answer 13

(x+2)(x+4) ---> if x = 2 ---> (2+2)(4+2)
if x = 4 ---> (4+2)(4+4)

Answer 14

same logic w/ choice C

Answer 15

(x-4)(x-2) ---> if x = 2 ---> (2-4)(2-2)
if x = 4 ---> (4-4)(4-2)

Answer 16

thats choice c^

Answer 17

correct? @Vocaloid

Answer 18

yes, so c would be your solution

Answer 19

http://prntscr.com/lvs9sn

Answer 20

any ideas? same logic as last time, what value(s) of x make x^2-64 = 0?

Answer 21

D

Answer 22

good but there's one more

remember that when you square a negative number it becomes positive

Answer 23

so also A?

Answer 24

yup good

Answer 25

http://prntscr.com/lvsbhc

Answer 26

hard to explain but try to choose the common factor shared by 24x^2, 12x^3, AND 4x^2y

notice how they are all multiples of 4 and all have at least x^2

Answer 27

2? I have no idea tbh

Answer 28

notice how they are all multiples of 4 and all have at least x^2

Answer 29

---> 4x^2

Answer 30

Ohh okay

http://prntscr.com/lvse6h

Answer 31

for each one try factoring the numerator and denominator. the correct solution should have a way for you to cross out something that's in both the numerator and denominator

Answer 32

Thats a lot of work lol

Answer 33

is their another way?

Answer 34

no

Answer 35

A: numerator: (x-3)(x+4) Denominator: cant factor

Answer 36

B: numerator: (2a+5b)(2a-5b) denominator: 2a(2a+5b)

Answer 37

good, notice anything about choice B?

Answer 38

C: numerator: 3(x+4) denominator: cant factor

D: numerator: (4x+3)(x^2+3) denominator: cant factor

Answer 39

B? hm not sure

Answer 40

for choice B notice how the numerator and denominator both have (2a+5b) in it, meaning you could cross them out

making B the solution for this problem

Answer 41

Ohh okay

http://prntscr.com/lvshuc

Answer 42

just need to apply FOIL to the numerator and denominator

Answer 43

can u show me the numerator and I do the denominator?

Answer 44

(x+4)(x-4) ----> first: x*4
outer: -4*x
inner: 4*x
last: 4(-4)
then you'd add them up