Question

Math check please

Answer 1

#3:
#5:
#12

Answer 2

@dude or @Vocaloid please check these whenever you get a chance

Answer 3

#3.png and #5.png I have done before

Answer 4

#12.png
We use the compound interest formula \[A(t) = A_0\left(1 + \frac{r}{n} \right)^{nt}\] where \(t\) is in years. We are given that \(A_0 = 51123.21\), \(r = \frac{2 + 3/8}{100} = 0.02375\), \(n = 12\cdot 30 = 360\) (with the assumption of 30 days per month), and \(t = 20 + 2/12 = 121/6\). Then \[A(121/6) = 51123.21\left(1 + \frac{0.02375}{360} \right)^{360 \cdot 121/6} \approx \$82531.59\] so the answer is $82531.59.