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Mathematics 13 Online
MARC:

Applications of the First Order ODE

MARC:

(Compounded Interest) Upon the birth of their first child, a couple deposited RM 5000 in an account that pays 8% interest compounded continuously. The interest payments are allowed to accumulate. How much will the account contain on the child’s eighteenth birthday ?

MARC:

\(P=Ae^{kt}\) \(t=0,P_0=5000\) \(t=1,P_1=5400\) \(5000=Ae^{k(0)}\) \(A=5000\) \(P=5000e^{kt}\) \(5400=5000e^{k(1)}\) \(\frac{27}{25}=e^k\) \(k=0.07696\) \(P=5000e^{0.07696t}\) \(t=18,P_{18}=?\) \(P_{18}=5000e^{0.07696(18)}\) \(P_{18}=19979.72\) Answer supposed to be \(21103.48\) but got a different answer >.<

dude:

\(5000e^{\large 0.08\times 18}\approx 21103.47908 ~or~ 21103.48\) The rate is 8%, so it is just 0.08 times 18 in the exponent xD

MARC:

yeah,got it bro,haha Thanks dude ;)

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