the nucleus of the helium atom contains two protons that are separated by about 3.0x10^-15 m. find the magnitude of the electrostatic force that each proton exerts on the other.

Question

jhonyy9 · Answer

any idea ?

Narad · Answer

Apply Coulomb's Law

$$F=k q_{1}q_{2}/r^{2}$$

The charge of a proton is $$q_{1}=q_{2}=1.6*10^{-19} C$$

The distance is $$r=3*10^{-15} m$$

The Coulomb's constant is $$k=8.99*10^{9} N m ^{2}/C^{2}$$

The force is $$F=8.99*10^{9} *(1.6*10^{-19})^{2}/(3*10^{-15})^{2}$$ N

=25.57N