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ging1995:
the nucleus of the helium atom contains two protons that are separated by about 3.0x10^-15 m. find the magnitude of the electrostatic force that each proton exerts on the other.
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jhonyy9:
any idea ?
Narad:
Apply Coulomb's Law \[F=k q_{1}q_{2}/r^{2}\] The charge of a proton is \[q_{1}=q_{2}=1.6*10^{-19} C\] The distance is \[r=3*10^{-15} m\] The Coulomb's constant is \[k=8.99*10^{9} N m ^{2}/C^{2}\] The force is \[F=8.99*10^{9} *(1.6*10^{-19})^{2}/(3*10^{-15})^{2}\] N =25.57N
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