Question

thanks

Answer 1

like a first step fourth root of 256 is equal 4 bc 4^4 = 256

Answer 2

Alright I think I got that....
I've been told that the answers are
4(cos 60 + i sin 60)
4(cos 150 + i sin 150)
4(cos 240 + i sin 240)
4(cos 330 + i sin 330)
but like I have no clue how they found these answers

Answer 3

you are given 256(cos 240° + i sin 240°).
compare this to r(cos(theta) + i sin(theta). your r-value is 256, your theta is 240 degrees, your n is 4 since you're calculating the fourth roots.
start with k = 0 and plug the n, theta, r, k, into the second line. repeat with k = 1, k = 2, k = 3.

Answer 4

For the first one is it supposed to look like this?
4√z = 4√256 [cos (240 +2pi0 / 4) + isin (240 +2pi0 / 4)]

Answer 5

yeah just be careful about parentheses

4√256 [cos ((240 +2pi0)/4) + isin ((240 +2pi0) / 4)

Answer 6

that should give you 4(cos 60 + i sin 60) after you simplify

Answer 7

okay! thanks! and are the other answers correct or no?

Answer 8

yes

Answer 9

thank you!

Answer 10

just a side note the formula i posted uses radians, since your problem is in degree use 360 instead of 2pi