Question

Suppose a binomial event has a probability of success of 0.3, and 1250 trials are performed. What is the standard deviation of the possible outcomes? Round your answer to two decimal places

Answer 1

any idea ?

Answer 2

The standard deviation for binomial distributions is:
Sqrt(npq)
N=trials=1250
P=p(success)=0.3
Q=p(failure)=1-p(success)=1-0.3=0.7
sqrt(1250×0.3×0.7)
I think you can solve that part now.