Find the area of a regular octagon with an apothem of 14.5 ft. Round to nearest tenth. I got 2030.3 ft^2
You know the apothem, being 14.5. You want to find the area. \(\bf{A=\frac{1}{2}ap}\) We need to find the perimeter. This means you need to identify the side length. So you would identify the interior angle of an octagon. An octagon has 8 sides. You would divide 360 by 8 to find the interior angle of each side. \(\bf{360 \div 8 = 45}\) Now you divide by 2 (so you can solve this with a right triangle). \(\bf{45 \div 2 = 22.5^{o}}\) So you have this... |dw:1554489930309:dw| Now solve by right triangle... |dw:1554490067616:dw| You would solve with the tan ratio. \(\large\bf{tan(22.5)=\frac{a}{14.5}}\) What would that equal?
6.006 ?
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