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@Vocaloid
Start with the general form ax^2 + bx + c Identify your a, b, and c terms by comparing the general form with the equation in the problem (be careful about negative signs) Then the x-coordinate of the vertex is -b/(2a) Then plug the x-coordinate into the equation to get max height
\[h(t)= -4.9t ^{2}+20t+65\] \[h^{'}(t)=-9.8t+20\] \[h ^{'}(t)=0\] when t=20/9.8=2.04 The maximum height is =\[-4.9*2.04^{2}+20*2.04+65=85.41m\]
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