Question

a student in Greece discovers a pottery bowl that contains 62% of its original amount of c-14

Answer 1

again any details and the question ???

Answer 2

The half life of C-14 is t =5570 yrs
The radioactive constant is
\[\lambda=\ln 2/t=\ln 2/5570= 0.0001244 \]
\[m _{t}/m _{0}=0.62\]
The age of the pottery is
\[T=1/\lambda*\ln (1/0.62) = 1/0.0001244*\ln(1/0.62)=3842.7\]
Age =3842.7years