Question

Find the equation of a line, in slope-intercept form of a line that passes through the point (9, 2) and is perpendicular to the line 2x - y = 8.

Answer 1

@Aeon

Answer 2

@dude

Answer 3

First you want to turn the equation they gave you into slope-intercept form (Isolate y)

Do you know how to do this?

Answer 4

The equation of the perpendicular line is
\[2x-y=8\]
\[y=2x-8\]
The slope is
\[m _{1}=2\]
When 2 lines are perpendicular, the product of their slopes is =-1
\[m _{1}*m _{2}=-1\]
Therefore, the slope of the line is
\[m _{2}=(-1)/(2)=-1/2\]
The equation of the line passing through (9,2) and slope=-1/2 is
\[(y-2)=-1/2(x-9)\]
\[y=-1/2x+9/2+2=-1/2x+13/2\]