Question

A sled travels 15 meters down a slope inclined at 30° with the horizontal. What is the horizontal displacement of the sled?

Answer 1

cos(theta) = adjacent/hypotenuse

Answer 2

uhhhhhh

Answer 3

theta is the angle
x is the adjacent side (which is what you want to solve for, the horizontal displacement)
15 is the hypotenuse

solve for x

Answer 4

I'm still confused

Answer 5

cos(30) = x/15 solve for x

Answer 6

2?

Answer 7

cos(30) = x/15

multiply both sides by 15 to get

x = cos(30) * 15 = ?

Answer 8

30?

Answer 9

remember that cos(30) is sqrt(3)/2

Answer 10

x = cos(30) * 15 = sqrt(3)/2 * 15 or about 12.99 in decimal form

Answer 11

no, I just said x = sqrt(3)/2 * 15 or about 12.99 in decimal form

Answer 12

oh look I am awful at algebra

Answer 13

thank you