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Chemistry 98 Online
ozzygirl1889:

If 25.0 mL of a 0.100 M aqueous sodium hydroxide is mixed with 25.0 mL of a 0.100 M aqueous hydrochloric acid in a calorimeter at an initial temperature of 23.0 degrees Celsius, what is the enthalpy change of this reaction if the final temperature reached in the calorimeter is 25.5 degrees Celsius? 
 NaOH + HCl --> NaCl + H2O

Narad:

The solutions of sodium hydroxide and hydrochloric acid have the same concentrations. NaOH + HCl -> NaCl + H2O Assume that the density = 1.00 Total volume = V= 50ml = 0.05L The number of moles of NaOH = number of moles of HCl is n=25*0.1*0.001=2.5*10^(-3) mol The specific heat of water is C = 4.18 J /(g* ºC) The change in temperature is T= (25.5-23)=2.5ºC The calorific change is Q=d*V*C*T = 1*50*4.18*2.5= 522.5 J The enthalpy change is H=Q/n= 522.5/0.0025=20900 J

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